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(F)=-5F^2+F-3
We move all terms to the left:
(F)-(-5F^2+F-3)=0
We get rid of parentheses
5F^2-F+F+3=0
We add all the numbers together, and all the variables
5F^2+3=0
a = 5; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·5·3
Δ = -60
Delta is less than zero, so there is no solution for the equation
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